2y^2=17

Solution for 2y^2=17 equation:

2y^2=17

We move all terms to the left:

2y^2-(17)=0

a = 2; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·2·(-17)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{34}}{2*2}=\frac{0-2\sqrt{34}}{4}
=-\frac{2\sqrt{34}}{4}
=-\frac{\sqrt{34}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{34}}{2*2}=\frac{0+2\sqrt{34}}{4}
=\frac{2\sqrt{34}}{4}
=\frac{\sqrt{34}}{2}
$